2x^2+17+60=x^2-3x-6

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Solution for 2x^2+17+60=x^2-3x-6 equation: 



2x^2+17+60=x^2-3x-6

We move all terms to the left:

2x^2+17+60-(x^2-3x-6)=0

We add all the numbers together, and all the variables

2x^2-(x^2-3x-6)+77=0

We get rid of parentheses

2x^2-x^2+3x+6+77=0

We add all the numbers together, and all the variables

x^2+3x+83=0

a = 1; b = 3; c = +83;
Δ = b2-4ac
Δ = 32-4·1·83
Δ = -323
Delta is less than zero, so there is no solution for the equation

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